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(F)=5F^2-8F-3
We move all terms to the left:
(F)-(5F^2-8F-3)=0
We get rid of parentheses
-5F^2+F+8F+3=0
We add all the numbers together, and all the variables
-5F^2+9F+3=0
a = -5; b = 9; c = +3;
Δ = b2-4ac
Δ = 92-4·(-5)·3
Δ = 141
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{141}}{2*-5}=\frac{-9-\sqrt{141}}{-10} $$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{141}}{2*-5}=\frac{-9+\sqrt{141}}{-10} $
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